Question #197712

the interaction between the magnetic fields produced by the magnet and the current in the wire produces forces on the magnet and wire. Compare these two factors


1
Expert's answer
2021-05-24T09:03:56-0400

Let the length of the magnet be l and the magnetic moment be m and we have to find the magnetic field at a distance r,

B1=μom4π(r3)\overrightarrow{B_1}=\frac{\mu_o m}{4\pi(r^3)}

Magnetic field due to the current carrying conductor,

B2=μoi2πr\overrightarrow{B_2}=\frac{\mu_o i}{2 \pi r}

Hence, the force between the two magnetic pole

F=B1B2A2μoF=\frac{B_1 B_2 A}{2\mu_o}

Now, substituting the values,

F=(μo2π)2miA2r4N\Rightarrow F = (\frac{\mu_o}{2\pi})^2\frac{miA}{2r^4}N


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