Question #197712

the interaction between the magnetic fields produced by the magnet and the current in the wire produces forces on the magnet and wire. Compare these two factors


Expert's answer

Let the length of the magnet be l and the magnetic moment be m and we have to find the magnetic field at a distance r,

B1=μom4π(r3)\overrightarrow{B_1}=\frac{\mu_o m}{4\pi(r^3)}

Magnetic field due to the current carrying conductor,

B2=μoi2πr\overrightarrow{B_2}=\frac{\mu_o i}{2 \pi r}

Hence, the force between the two magnetic pole

F=B1B2A2μoF=\frac{B_1 B_2 A}{2\mu_o}

Now, substituting the values,

F=(μo2π)2miA2r4N\Rightarrow F = (\frac{\mu_o}{2\pi})^2\frac{miA}{2r^4}N


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