Question #197147

Test instrument to measure magnetic field strengths are often based on the Hall Effect. In one instrument the “probe” is a 1.0-mm- thick, 6.0-mm - wide semiconductor with a charge-carrier density of 2.1x 1021 m-3 , much less than the charge-carrier density in a conductor.

Passing a 60 mA current through the probe generates a Hall voltage of 120 mV. What is the magnetic field strength?


1
Expert's answer
2021-05-24T16:52:11-0400

The Hall voltage is given by

VH=IBnedV_H=\frac{IB}{ned}

where II is current,

BB is magnetic field,

nn is charge-carrier density,

ee is charge of electron,

dd is thickness of the "probe"


Then:


B=VHnedI=1202.110211.6101910360=0.672 TB=\frac{V_Hned}{I}=\frac{120\cdot2.1\cdot10^{21}\cdot1.6\cdot10^{-19}\cdot10^{-3}}{60}=0.672\ T


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