Question #196812

Find the volume charge density associated with a field given by D= (xy²)i + (yx²)j + (z) C/m²


1
Expert's answer
2021-05-24T14:14:07-0400

The given electric field is associated with D =(xy2)i^+(yx2)j^+z c/m2(xy^{2}) \hat{i}+(yx^{2})\hat{j}+z\ c/m^{2}


now , we have to find out volume charge density with the help of given field function , the relation between the Electric field and volume charge density is given by -


volume charge density is denoted by ρ\rho = .D{\nabla}.D


=xi^+yj^+zk^{\nabla}=\dfrac{\partial}{\partial x}\hat{i}+\dfrac{\partial}{\partial y}\hat{j}+\dfrac{\partial}{\partial z}\hat{k}


ρ\rho =(xy2)xi^+(yx2)yj^+(z)zk^=\dfrac{\partial(xy^{2})}{\partial x}\hat{i}+\dfrac{\partial(yx^{2})}{\partial y}\hat{j}+\dfrac{\partial(z)}{\partial z}\hat{k}


ρ=y2i^+x2j^+k^\rho=y^{2}\hat{i}+x^{2}\hat{j}+\hat{k} c/m3c/m^{3}



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