A field of E=100 v/m is kept in copper. Determine the power loss per volume
ω=δQdV⋅dt=E2/ρ=1002/1.75⋅10−8=5.7⋅1012 (J/(m3⋅s))\omega=\frac{\delta Q}{dV\cdot dt}=E^2/\rho=100^2/1.75\cdot10^{-8}=5.7\cdot10^{12} \ (J/(m^3\cdot s))ω=dV⋅dtδQ=E2/ρ=1002/1.75⋅10−8=5.7⋅1012 (J/(m3⋅s))
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