Question

Calculate the energy density in an electric field of 10⁶ V/m

Answer 1

Given,

$E = 10^6V/m$

We know that,

$\epsilon_0 = 8.85 \times 10^{-12}$

The energy density formula of the capacitor is given by:

$U = \dfrac{1}{2}\epsilon_0E^2$

$U = \dfrac{1}{2}(8.85 \times 10^{-12} \times 10^{12})$

$U = 4.425$