It is known that the relative permeability of iron is 100. If the mean atomic dipole moment is equal to 2microB . Find the magnets of magnetization M ?
M=Bμμ0=2⋅10−6100⋅4π⋅10−7=16 mAm.M=\frac{B}{\mu \mu_0}=\frac{2\cdot 10^{-6}}{100\cdot 4\pi\cdot 10^{-7}}=16~\frac{mA}{m}.M=μμ0B=100⋅4π⋅10−72⋅10−6=16 mmA.
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