Determine the force of 1microcoulomb from a large metal plate to be grounded
Answer :-
F=q216π∈d2F={q2\over16π∈d^2}F=16π∈d2q2
F=(1×10−6)216π∈d2F=({1×10^{-6})^2\over16π∈d^2}F=(16π∈d21×10−6)2
F=10−1216π∈d2F={10^{-12}\over16π∈d^2}F=16π∈d210−12
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