Question

For a circular current element of radius, b = 6 m, determine the magnetic field H on the axis of the loop if

 I = 4A, h = 6 m. Also find H at the center of the loop.

Answer 1

$H_h=\frac{b^2I}{2(h^2+b^2)^\frac 32}=\frac{6^2\cdot 4}{2\cdot(6^2+6^2)^\frac 32}=0.118~\frac Am,$

$H_0=\frac {I}{2b}=\frac{4}{2\cdot 6}=0.333~\frac Am.$