Question

An in homogeneous magnetic field B(r,z) is independent of r and the z dependence is given by:

$B(0,z)=B_0\frac{z}{L}$

where L is constant. A circular loop of wire has a radius a, resistance R,and an axis which coincides with the z axis.

If the loop moves with a constant velocity v in the z direction, what current flows in the coil ?

Answer 1

Given,

Magnetic field $B(0,z)=\frac{B_o. z}{L}$

Where L is constant.

Radius of the circular loop = r

Area of the loop $=\pi r^2$

Magnetic flux = $B(0,z).A$

$=\frac{B_oz\pi r^2}{L}$

As for this case, conducting ring which have radius R is moving in the direction of magnetic field so change in magnetic flux will be zero.

hence no emf will get generate, so current will not flow in the circular loop.