Question #190407

 The equation for an alternating current is given by i = 77 sin 314t. Find the peak current, 

frequency, time period and instantaneous value of current at t = 2 ms


1
Expert's answer
2021-05-09T15:09:18-0400

Solution:-


Equation in general form

i(t)=ImSin(2πft)i(t)=I_m \cdot Sin{(2 \pi f \cdot t)}


Now,


Peak current Im=77AI_m=77A


Frequency f=3142π=31423.14=501sf=\frac{314}{2\pi}=\frac{314}{2\cdot 3.14}=50 \frac{1}{s}


Time period T=1f=150=0.02sT=\frac{1}{f}=\frac{1}{50}=0.02s


Instantaneous value at t=2 ms.


i(0.002)=77Sin(3140.002)=45.24Ai(0.002)=77 \cdot Sin{(314 \cdot 0.002)}=45.24A



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