Question #189706

An external magnetic field changes as a function of time such that: (1) it is momentarily zero at time t=0t=0 , and (2) it produces an electric field E=xy^yz^E=x\hat{y}-y\hat{z} that is constant in time. Determine the magnitude and direction of the magnetic field as a function of time


1
Expert's answer
2021-05-06T17:23:07-0400

Given,

Electric field is given as (E)=xy^yz^(E)= x\hat{y}-y\hat{z}

We know that,

×E=dBdt\Rightarrow \nabla \times E=\frac{-dB}{dt}


[xi^+yj^+xz^]×[xy^yz^]=dBdt\Rightarrow [\frac{\partial }{\partial x}\hat{i}+\frac{\partial }{\partial y}\hat{j}+\frac{\partial }{\partial x}\hat{z}]\times[x\hat{y}-y\hat{z}]=-\frac{dB}{dt}


i^+k^=dBdt\Rightarrow \hat{i}+\hat{k}=\frac{-dB}{dt}

B=t(i^+k^)B= -t(\hat{i}+\hat{k})



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