What is the force between two 1.0 X 10-5 C charges separated by 2.0 m?
Answer:-
Using Coulomb's law
F=kq1q2r2F= k{q_1q_2\over r^2}F=kr2q1q2
=9×109(1×10−5)×(1×10−5)22=9×10^9{(1×10^{-5})×(1×10^{-5})\over 2^2}=9×10922(1×10−5)×(1×10−5)
=0.225N=0.225 N=0.225N answer
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