Two charged spheres exert a force of 5.54 × 10-4 N on each other. If one of the spheres has a charge of 3.72 × 10-9 C and the other sphere has a charge of 4.32 × 10-6 C, how far apart are the charged spheres?
F=kq1q2r2 ⟹ F=\frac{kq_1q_2}{r^2}\impliesF=r2kq1q2⟹
r=kq1q2F,r=\sqrt{\frac{kq_1q_2}{F}},r=Fkq1q2,
r=9⋅109⋅3.72⋅10−9⋅4.32⋅10−65.54⋅10−4=51 cm.r=\sqrt{\frac{9\cdot 10^9\cdot 3.72\cdot 10^{-9}\cdot 4.32\cdot 10^{-6}}{5.54\cdot 10^{-4}}}=51~cm.r=5.54⋅10−49⋅109⋅3.72⋅10−9⋅4.32⋅10−6=51 cm.
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