Question #189323

 Two straight, parallel, current-carrying wires separated by a distance of 5cm contain the same 1000 A current, flowing in similar directions. Determine the force per unit length exerted by the two wires.



1
Expert's answer
2021-05-10T09:23:25-0400

We have given that,

I1=I2=1000AI_1=I_2 = 1000A

r=5cm=0.05mr = 5cm = 0.05m

We know the formula,

Fl=μ0I1I22πr\dfrac{F}{l} = \dfrac{\mu_0I_1I_2}{2\pi r} =4π×107×1000×10002×3.14×0.05=4Nm1= \dfrac{4\pi \times 10^{-7}\times1000 \times 1000 }{2 \times 3.14 \times0.05} = 4Nm^{-1}


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