Question #189322

   A 5cm long solenoid has 1500 turns of wire and carries a current of 7 A. Calculate the magnetic field at the center of the solenoid. 



Expert's answer

We have given that,

L=5cm=0.05mL = 5cm = 0.05m

N=1500N = 1500

I=7AI = 7A ,

The magnetic field at the centre of the solenoid.

B=μ0NILB = \dfrac{\mu_0NI}{L}


=4×π×107×1500×70.05= \dfrac{4 \times \pi \times10^{-7} \times 1500 \times 7}{0.05}


== 2637600×107T2637600 \times 10^{-7}T



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