A 5cm long solenoid has 1500 turns of wire and carries a current of 7 A. Calculate the magnetic field at the center of the solenoid.
We have given that,
L=5cm=0.05mL = 5cm = 0.05mL=5cm=0.05m
N=1500N = 1500N=1500
I=7AI = 7AI=7A ,
The magnetic field at the centre of the solenoid.
B=μ0NILB = \dfrac{\mu_0NI}{L}B=Lμ0NI
=4×π×10−7×1500×70.05= \dfrac{4 \times \pi \times10^{-7} \times 1500 \times 7}{0.05}=0.054×π×10−7×1500×7
=== 2637600×10−7T2637600 \times 10^{-7}T2637600×10−7T
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Dear john, 4\pi10e-7 is a definition of the the vacuum permeability \mu_0
i just want to know where did the 4xpix10^-7 and also the 0.05 came from?
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Dear john, 4\pi10e-7 is a definition of the the vacuum permeability \mu_0
i just want to know where did the 4xpix10^-7 and also the 0.05 came from?