Question

  An electron is moving east at 5x106 m/s. Determine the magnetic field from a point north east with a distance of 5cm. 

Answer 1

$\bar{B}= \frac{\mu_0}{4 \pi} \frac{qvsin \theta}{r^3}$

$\bar{B}= \frac{1.2566 *10^{-6}}{4 \pi} \frac{1.60217662 *10^{-19}*5*10^6*sin45}{(0.05)^3}$

$\bar{B}=5.45303 \times 10^{-16} T$