Question #189308

What will happen to the dipole when it place inside the

uniform Electric Field

NOTE:. Your Assignment should cover following points

• What is a dipole

• what is force acting on dipole

• what is torque on dipole

• expression for potential energy of d

ipole


1
Expert's answer
2021-05-05T17:38:31-0400

Dipole:-


The product of magnitude of negative or positive charge(q) and the distance between the centres of the positive and negative charges is called dipole


p=qdp=|q|d

Unit =C×m=C\times m

(b)



An electric dipole experiences a net electric force if the positive charge q is subject to an electric field E (r + d) that differs from E(r) acting on the negative charge q.

At d distance force

F=qEF=qE

At d+∆d distance force

F=q[E(r+d)Er]F=q[E(r+d)-Er]

Fx=q[Ex(x+dx,y+dy,z+dz)Ex(x,y,z)]F_{x}=q[E_{x}(x+dx,y+dy,z+dz)-E_{x}(x,y,z)]

We can express this equation


Fx=q[Ex,(x,y,z)+dxExx+dyEyy+dzEzz+.............................Ex,(x,y,z)]F_{x}=q[E_{x,}(x,y,z)+d_{x}\frac{\partial {E_{x}}}{\partial x}+d_{y}\frac{\partial {E_{y}}}{\partial y}+d_{z}\frac{\partial {E_{z}}}{\partial z}+............................. -E_{x,}(x,y,z)]

First and last term cancel

Then we can written as

Fx=p.ExF_{x}=p.\nabla E_{x}


y components

Fy=p.EyF_{y}=p.\nabla E_{y}


z components

Fz=p.EzF_{z}=p.\nabla E_{z}

Summarized in vector expression

F=p.E(1)F=p.\nabla E \rightarrow(1)

(c) torque of dipole

τ=p×E\overrightarrow{\tau}=\overrightarrow{p}\times\overrightarrow{E}

τ=pEsinθ\tau=pEsin\theta

Where P =qd

(d) Potential energy

U=p.EU=-\overrightarrow{p}.\overrightarrow{E}

U=pEcosθU=-pEcos\theta



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