Question #187922

Electric field at point p(2m,1m,2m) due to a point charge 5.0 muC placed at origin is


1
Expert's answer
2021-05-04T12:06:43-0400

Find the distance squared from the origin to the point:


D2=22+12+22=9 m2.D^2={2^2+1^2+2^2}=9\text{ m}^2.

The field at this point:


E=kQD2=4993 V/m.E=\frac{kQ}{D^2}=4993\text{ V/m}.


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