Question

Find the force on an electron if it is placed at a point where the electric field intensity is 240 N/C directed to the right.

Answer 1

Force on charge when placed in electric field=$q\ E$

Where q=charge of an electron =$1.6012\times 10^{-19}\ C$

E=electric field

F= qE =$1.6012\times10^{-19}\times240=3.42888\times 10^{-19}\ N$