Determine the permittivity of a dielectric within a capacitor stores 60 Mf worth or charge has an area of 0.5 m² for each plate and 2.0 X 10^-⁴ m apart.
Answer
Capacitance is given by
C=ϵ0KAdC=\frac{\epsilon _0KA}{d}C=dϵ0KA
K is permittivity of dielectric medium.
K=CdAϵ0=60×10−6×2.0×1040.5×8.85×10−12=2711.86K=\frac{Cd}{ A \epsilon _0 }\\=\frac{60\times10^{-6}\times 2.0 \times10^-⁴ }{ 0.5\times8.85\times10^{-12}}\\=2711.86K=Aϵ0Cd=0.5×8.85×10−1260×10−6×2.0×104=2711.86
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