Question #185724

Solve for the magnetic flux through a loop with an area of 8.5 ✕ 10 -4 m2 found perpendicular to a magnetic field with magnitude 0.75 T.



1
Expert's answer
2021-04-26T16:48:39-0400

ϕ=BAcosθ\phi=BAcos \theta

Where B=0.75T;A=8.5×104θ=0B=0.75T; A= 8.5 \times 10^{-4} \theta =0

ϕ=0.75×8.5×104=6.375×104T.m2\phi = 0.75 \times 8.5 \times 10^{-4}=6.375 \times 10^{-4} T.m^2


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