Question #185629

A charged particle is moving without deflection in a space region where an elec- tric field E = 3.5x102V/m and a magnetic field B = 0.25T act in perpendicular directions.

Calculate the speed of the particle.


1
Expert's answer
2021-04-26T19:04:58-0400

To be given in question

Electric field (E)=3.5×102volt/meter3.5\times10^2volt/meter

Magnetic field(B)=0.25tesla

To be asked in question

Speed of particle=?

We know that

E=B×vE=B\times v

E=Bvsinθ(1)E=Bvsin\theta\rightarrow(1)

Eqution (1)put values

3.5×102=0.25×v×sin90°3.5\times10^2=0.25\times v\times sin90°

v=3.5×1020.25=1400meter/secv=\frac{3.5\times 10^2}{0.25}=1400meter/sec

v=1.4×103meter/secv=1.4\times10^3 meter/sec



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