Question

An 88.30-cm wire that carries an electric current of 1.35 A perpendicular to the field has experienced a magnetic force of 9.0✕10 -3 N. Solve for the magnitude of the magnetic field that caused this force.

Answer 1

To be given in question

Current (i)=1.35 Amp

Magnetic force (f)=$9\times10^{-3} N$

Wire length $(l)=88.30 \times 10^{-2}meter$

Magnetic force (F_B)=$9\times10^{-3}N$

$\theta=90°$

To be asked in question

Magnetic field (B)=?

We know that

$F=I(l\times B)$

$F=IlBsin\theta$

$\theta =90°$

Put value

$F =IlB\rightarrow(1)$

$B=\frac{F}{lI}$

$B=\frac{9\times10^{-3}}{88.30\times10^{-2}\times1.35}$ =0.00755 T