Question

The square surface measures 3.2mm on each side. It is immersed in a uniform electric field with E=1800 N/C. the field lines make an angle of 65 with the outward ponting normal. calculate the flux through the surface

Answer 1

$\Phi=EAcos\theta=El^2cos\theta,$

$\Phi=1800\cdot(3.2\cdot10^{-3})^2\cdot0.42=7.7\cdot 10^{-3}~Vm.$