Question #180857

Calculate the value of α, β, γ ,η for a rubber at a frequency f=106 Hz. It is given that εr = 3.5, σ=10-16 mhos/m & µr=1.   


1
Expert's answer
2021-04-19T07:21:39-0400

α=πfμ0σ=21010 Npm.\alpha=\sqrt{\pi f \mu_0 \sigma}=2\cdot 10^{-10}~\frac{Np}{m}.

β=2πϵrc=4.11010 radm.\beta=\frac{2\pi\sqrt{\epsilon_r}}{c}=4.1\cdot 10^{-10}~\frac{rad}{m}.

η=120π Ω,\eta=120\pi~\Omega,

η1=ηϵr=64π Ω,\eta_1=\frac{\eta}{\sqrt{\epsilon_r}}=64\pi~\Omega,

γ=ηη1η+η1=0.3.\gamma=\frac{\eta-\eta_1}{\eta+\eta_1}=0.3.


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS