Calculate the value of α, β, γ ,η for a rubber at a frequency f=106 Hz. It is given that εr = 3.5, σ=10-16 mhos/m & µr=1.
α=πfμ0σ=2⋅10−10 Npm.\alpha=\sqrt{\pi f \mu_0 \sigma}=2\cdot 10^{-10}~\frac{Np}{m}.α=πfμ0σ=2⋅10−10 mNp.
β=2πϵrc=4.1⋅10−10 radm.\beta=\frac{2\pi\sqrt{\epsilon_r}}{c}=4.1\cdot 10^{-10}~\frac{rad}{m}.β=c2πϵr=4.1⋅10−10 mrad.
η=120π Ω,\eta=120\pi~\Omega,η=120π Ω,
η1=ηϵr=64π Ω,\eta_1=\frac{\eta}{\sqrt{\epsilon_r}}=64\pi~\Omega,η1=ϵrη=64π Ω,
γ=η−η1η+η1=0.3.\gamma=\frac{\eta-\eta_1}{\eta+\eta_1}=0.3.γ=η+η1η−η1=0.3.
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