A wire of length 0.050𝑚 and carries a current 𝐼 is in a horizontal uniform magnetic field B of 2.50 𝑇 which is perpendicular to the rod. The weight of the wire is 0.80𝑁. What is the value of the current 𝐼 if the magnetic force on the wire equals its weight?
To be given in question
Magnetic field=2.50 T
Force (F)=0.80N
Length (L)=0.050meter
"\\theta=90\u00b0"
To be asked in question
Current "(I)" =?
We know that
"F=i(l\\times B)"
"F=ilBsin\\theta"
"sin90\u00b0=1"
"F=ilB"
Put value
"0.80=i\\times0.050\\times2.50"
"i=6.4 Ampear"
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