Question

 A wire of length 0.050𝑚 and carries a current 𝐼 is in a horizontal uniform magnetic field B of 2.50 𝑇 which is perpendicular to the rod. The weight of the wire is 0.80𝑁. What is the value of the current 𝐼 if the magnetic force on the wire equals its weight?

Answer 1

To be given in question

Magnetic field=2.50 T

Force (F)=0.80N

Length (L)=0.050meter

$\theta=90°$

To be asked in question

Current $(I)$ =?

We know that

$F=i(l\times B)$

$F=ilBsin\theta$

$sin90°=1$

$F=ilB$

Put value

$0.80=i\times0.050\times2.50$

$i=6.4 Ampear$