Question

negative charge of -200 uC and a positive charge of 800 uC are separated by a distance of 0.30 cm.

Answer 1

We have given that,

$q_1 = -200 \mu C$

$q_2 = 800 \mu C$

$d = 0.30cm$

Then force exerted F can be calculated as,

$F = \dfrac{1}{4\pi \epsilon_0} \times \dfrac{q_1q_2}{d^2}$

$F = \dfrac{9\times 10^9 \times -200 \times 10^{-6}\times 800 \times 10^{-6}}{0.30 \times 0.30}$

$F = 10.67 \times 10^3 N$