Question

A copper wire has a resistance of 15.0 ohms at a temperature of 14 C. After a current passes through the windings, the resistance rose to 125 ohms. To what temperature was the wire heated?

Answer 1

$$R=R_{ref}[1+\alpha(T-T_{ref)}],$$ $$T=\dfrac{\dfrac{R}{R_{ref}}-1}{\alpha}+T_{ref},$$ $$T=\dfrac{\dfrac{125\ \Omega}{15\ \Omega}-1}{0.004041\ ^{\circ}C^{-1}}+14^{\circ}C=1829^{\circ}C.$$