Question #174042

Find electrical potential due to Ring at a point P.  The point P is lies at distance Z from the origin along the Z- axis.


1
Expert's answer
2021-03-23T11:16:19-0400
V=kr1dqV=k02πλRdθz2+R2V=2πkλRz2+R2V=kqz2+R2V=k\int r^{-1}dq\\V=k\int^{2\pi}_0\frac{\lambda Rd\theta}{\sqrt{z^2+R^2}}\\V=\frac{2\pi k\lambda R}{\sqrt{z^2+R^2}}\\ \\V=\frac{kq}{\sqrt{z^2+R^2}}

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