Question #173751

derive the expression for penetrating depth of magnetotelluric signals


1
Expert's answer
2021-03-23T08:09:13-0400

Electric-magnetic phenomena can be represented by the Maxwell's equations. 

J(t)+t(D(t))J(t)+\frac{\partial \:}{\partial \:t}\left(D(t\right))

Solution to Maxwell's equations in simple medium

Ex=Aekz+Be+kzE_x = A e^{−kz}+B e^{+kz}

Hy=kiωμ0(Aekz+Be+kz)H_y = \frac{k}{iω \mu_0}(A e^{−kz}+B e^{+kz})

The homogenous in 1 D

Ex=AekzE_x = A e^{−kz}

k=iωμ0/ρk =\sqrt{ iω \mu_0/\rho}

Hy=kiωμ0(Aekz)H_y = \frac{k}{iω \mu_0}(A e^{−kz})

At Ex(z=0)=A    Ex(z=δ)=A/eE_x (z=0)= A \implies E_x(z=\delta) = A/ e

Therefore, penetrating depth of magnetotelluric signals, δ=2ρiωμ0\delta =\sqrt{ \frac{2 \rho}{iω \mu_0}}

Where ω=2πfω= 2 \pi f


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