Question #172691

Two stationary frictionless pucks are placed on a level surface at an initial distance of 3.0m. The mass of puck 1 is 0.55kg and it has a charge of

+5.0 x 10-4C,

while puck 2 has a mass of 0.25kg and a charge of +3.5 x 10-4C. Find the velocity of each puck after they have moved very far apart.


1
Expert's answer
2021-03-18T14:02:39-0400

F1=Gm1m2r2,F_1=\frac{Gm_1m_2}{r^2},

F2=kq1q2r2,F_2=\frac{kq_1q_2}{r^2},

p1=m1v1,p_1=m_1v_1,

p2=m2v2,p_2=m_2v_2,

{(F2F1)r=m1v122+m2v222p1=p2\begin{cases} (F_2-F_1)r=\frac{m_1v_1^2}{2}+\frac{m_2v_2^2}{2}\\ p_1=p_2 \end{cases}

{2kq1q2r2Gm1m2r=m1v12+m2v22m1v1=m2v2\begin{cases} \frac{2kq_1q_2}{r}-\frac{2Gm_1m_2}{r}=m_1v_1^2+m_2v_2^2 \\ m_1v_1=m_2v_2 \end{cases}

where

v1=2m2(kq1q2Gm1m2)m1r(m1+m2)v_1=\sqrt{\frac{2m_2(kq_1q_2-Gm_1m_2)}{m_1r(m_1+m_2)}}

v2=2m1(kq1q2Gm1m2)m2r(m1+m2)v_2=\sqrt{\frac{2m_1(kq_1q_2-Gm_1m_2)}{m_2r(m_1+m_2)}}

v124.4 msv_1\approx 24.4~\frac ms

v253.7 msv_2\approx 53.7~\frac ms


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