Question #171472

A linearly polarized wave with Ē in the xy plane is incident from x > 0 on an interface at x = 0. In the region x > 0 is free space and in the region x< 0 is a medium with dielectric constant e,

a) If the incidence angle is 45 degrees and angle of transmitted(refracted wave) is 90 degree find the dielectric constant ?

b)Find E and B for z>0 and calculate the time average of Poynting vector component along x (i.e. Sx) flowing through x = 0.


1
Expert's answer
2021-03-14T19:13:12-0400

Let's draw the diagram for the given condition,



For the region (i), x<0

For the region (ii), x>0

Permittivity for the free space (ϵo)=1(\epsilon_o)=1

Here y-z is the interface between the two medium.

Now, using the electric field

For the boundary condition,

EI=EII...(i)E_I''=E_{II}'' ...(i)

The perpendicular component of D is noncontinuous function,

DIDII=σfD_{I}^{\perp}-D_{II}^{\perp}=\sigma_f

Electric displacement vector D=ϵE\overrightarrow{D}=\epsilon \overrightarrow{E}

DI=DIID_{I}^{\perp}=D_{II}^{\perp}

EI=EIIsin(π/4)=EII2E_{I}''=E_{II}\sin(\pi/4)=\frac{E_{II}}{\sqrt{2}}

Now, substituting the values,

ϵIEI=ϵIIEII\epsilon_{I} \overrightarrow{E}_{I}^{\perp}=\epsilon_{II} \overrightarrow{E}_{II}^{\perp}

ϵ=\epsilon=\infty

b) E\overrightarrow{E} is linearly polarized in x-y plane

We know that poynting vector S=E×Bμo\overrightarrow{S}=\frac{\overrightarrow{E}\times \overrightarrow{B}}{\mu_o}

E=E2(i^+j^)\overrightarrow{E}=\frac{E}{\sqrt{2}}(\hat{i}+\hat{j})


B=E2cB=\frac{E}{\sqrt{2}c}

S=<S>S=<|\overrightarrow{S}|>

=E22μc=\frac{E^2}{\sqrt{2}\mu c}

=0.002E2=0.002E^2



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