Question

Equal charges of 3x10^-9 are situated at the three corners of a square of side 5.20 m. Find the potential at the unoccupied corner.

Answer 1

Answer

Potential due to single charge at distance r is given by

$V=\frac{kq}{r}$

Potential at unoccupied corner can be written as

$V=\frac{(9\times10^{9}) (3\times10^9)}{5.20^2}(1+\frac{1}{\sqrt{2}}) =1.7volts$