Question #168003

A 6.0 kg object that is 3.0 m from the surface of the Moon has 28.8 J of gravitational potential energy. What is the value of g?

(Gravitational field strength/Gravitational acceleration)


Stuck trying to reverse logic this problem... If anyone has any steps using Eg=mgh I would appreciate it.


Expert's answer

The gravitational potential energy:


E=mgh28.8=(6)(3)gg=1.6ms2E=mgh\\28.8=(6)(3)g\\g=1.6\frac{m}{s^2}


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