Question

Calculate the magnitudes of magnetic intensity

H and the magnetic field B at the centre of a 2000-turn solenoid which is 0.50 m long and carries a current of

1A.

Answer 1

The magnetic field $B$ can be found as follows:

$$B=\mu_0\dfrac{N}{L}I,$$ $$B=4\pi\cdot10^{-7}\ \dfrac{Tm}{A}\cdot\dfrac{2000\ turn}{0.5\ m}\cdot1\ A=5.02\cdot10^{-3}\ T.$$

The magnetic intensity $H$ can be found as follows:

$$B=\mu_0H,$$ $$H=\dfrac{B}{\mu_0}=\dfrac{5.02\cdot10^{-3}\ T}{4\pi\cdot10^{-7}\ \dfrac{Tm}{A}}=3997\ \dfrac{A}{m}.$$