Question

 A certain resistor has a resistance of 212.1Ω at 25⁰C and a resistance of 214.2 Ω at 50⁰C. What is its temperature coefficient of resistivity?

Answer 1

$\alpha=\frac{\Delta R}{R_0 \Delta t},$

$\alpha=\frac{214.2-212.1}{212.1(50-25)}=(396\cdot10^{-6})°C^{-1}.$