Question #165293

Two electric charges q1 and q2 are initially separated by distance ri . When the two charges are moved farther apart, the magnitude of the electric force reduces three times the initial. How many times the separation distance between them increases?


1
Expert's answer
2021-02-22T10:22:54-0500

According to the Coulomb's law the electric force is proportional to the product of charges and proportional to r2.r^{-2}.

F=kq1q2r2.F = \dfrac{kq_1q_2}{r^2}.


Therefore, if the force reduces three times the initial, then the distance increases as 31.73.\sqrt{3}\approx 1.73.


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