Question #165293

Two electric charges q1 and q2 are initially separated by distance ri . When the two charges are moved farther apart, the magnitude of the electric force reduces three times the initial. How many times the separation distance between them increases?


Expert's answer

According to the Coulomb's law the electric force is proportional to the product of charges and proportional to r2.r^{-2}.

F=kq1q2r2.F = \dfrac{kq_1q_2}{r^2}.


Therefore, if the force reduces three times the initial, then the distance increases as 31.73.\sqrt{3}\approx 1.73.


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