Question

What is the magnitude of the intensity at a point which is 0.3 m from a 10 µC charge? (Show your solution)

Answer 1

Given,

Distance (d) = 0.3m

Charge $(Q)=10 \mu C =10\times 10^{-6}C$

$=10^{-5}C$

Hence, the required electric field $(\overrightarrow{E}) = \frac{Q}{4\pi \epsilon_o d^2}$

Now, substituting the values,

$\Rightarrow \overrightarrow{E}=\frac{10^{-5}\times 9\times 10^{9}}{0.3^2}N/C$

$\Rightarrow \overrightarrow{E}=\frac{9\times 10^4}{0.09}N/C$

$\overrightarrow{E}=1\times 10^6 N/C$