A torold Has 750 turns the radius of the circle through the centre of its winding is 5 cm what current in the winding will produce in magnetic field of 1.8x10-3 tangent to this central circle
2πrB=μ0NI,2\pi rB=\mu_0 NI,2πrB=μ0NI,
I=2πrBμ0N,I=\frac{2\pi rB}{\mu_0 N},I=μ0N2πrB,
I=2π⋅0.05⋅1.8⋅10−34π⋅10−7⋅750=0.6 A.I=\frac{2\pi \cdot 0.05\cdot1.8\cdot 10^{-3}}{4\pi\cdot 10^{-7}\cdot 750}=0.6~\text{A}.I=4π⋅10−7⋅7502π⋅0.05⋅1.8⋅10−3=0.6 A.
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