Find the electric flux through the surfaces 1 to 5 in the figure below. Height of the object is 2.0 m Width is 4.0 m. The object is angled at 30 degrees with E equalling 400 N/C
Answer
Flux
ϕ=EAcosθ=400×2×4cos30°=2.8KWb\phi=EAcos\theta\\=400\times2\times4\cos30°\\=2.8KWbϕ=EAcosθ=400×2×4cos30°=2.8KWb
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