In a magnetic field of 400A per m, the relative permeability of a piece of soft iron is 3000.Find the magnetic induction in the iron at this field strength?
Answer
Magnetic field strength can be given as
B=μrμ0HB=(3000)(4π×10−7)(400)B=1.5TB=\mu_r\mu_0H\\B=(3000) (4\pi \times10^{-7}) (400) \\B=1.5TB=μrμ0HB=(3000)(4π×10−7)(400)B=1.5T
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