A bob on the end of a spring is pulled and released.If the bob moves up and down 12 times in 3.6 seconds, determine the period and frequency of the oscillation.
T=tn=3.612=0.3 s,T=\frac tn=\frac {3.6}{12}=0.3 ~s,T=nt=123.6=0.3 s,
ν=1T=10.3=3.3 Hz.\nu=\frac 1T=\frac{1}{0.3}=3.3 ~Hz.ν=T1=0.31=3.3 Hz.
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