A point charge of 1x 10-6C is at centre of Gaussian surface with cubical shape 1m on edge. Find flux through surface?
Answer
Using Gauss's Law
Flux is given by
ϕ=qϵ0\phi=\frac{q}{\epsilon_0}ϕ=ϵ0q
ϕ=1×10−68.85×10−12=113\phi=\frac{ 1\times10^{-6} }{ 8.85\times10^{-12} }=113ϕ=8.85×10−121×10−6=113 KiloWeber
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