A material has conductivity of 10-2 mho/m and a relative permittivity of 4. The frequency at which conduction current in the medium is equal to displacement current is
Answer
Frequency can be given as
f=σ2πϵ=10−22π×4×8.85×10−12=45MHzf=\frac{\sigma }{2\pi \epsilon}=\frac{10^{-2}}{2\pi \times4\times8.85\times10^{-12}}=45MHzf=2πϵσ=2π×4×8.85×10−1210−2=45MHz
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