The electric field in free space is given by E= 50cos (102t+beta x) ay
1,find the direction of wave propogation
Given, E=50Cos(102t+βx)ayE=50Cos(10^{2}t+\beta x)a_{y}E=50Cos(102t+βx)ay
Compare the above equation with the standard equation;
E=E0Cos(ωt−βx)ayE=E_{0}Cos(\omega t-\beta x)a_{y}E=E0Cos(ωt−βx)ay
So, E0=50E_{0}=50E0=50
Direction of propagation =−ax=-a_{x}=−ax i.e. −x-x−x directiondirectiondirection
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments