Question #153623

What is magnetic field due to toroid.


Expert's answer

Bdl=μ0IB2πr+R2=μ0NI\int Bdl=\mu_0I\to B\cdot2\pi\cdot\frac{r+R}{2}=\mu_0NI\to


B=μ0NIπ(r+R)B=\frac{\mu_0NI}{\pi(r+R)} . Answer

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