What is magnetic field due to toroid.
∫Bdl=μ0I→B⋅2π⋅r+R2=μ0NI→\int Bdl=\mu_0I\to B\cdot2\pi\cdot\frac{r+R}{2}=\mu_0NI\to∫Bdl=μ0I→B⋅2π⋅2r+R=μ0NI→
B=μ0NIπ(r+R)B=\frac{\mu_0NI}{\pi(r+R)}B=π(r+R)μ0NI . Answer
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