Question

Alpha particles are made of two protons and two neutrons.

mp=1.673x10^-27  kg;mn =1.675x10^-27 kg;qe =1.60x10^-19C

-Find the electric force acting on an alpha particle in a vertical electric field of 7.00 x 10^2 N/C.

-What is the acceleration of this alpha particle?

Answer 1

1)

$F=qE=2q_eE=2\cdot1.60\cdot 10^{-19}\cdot7.00\cdot10^2=2.24\cdot10^{-16}~N.$

2)

$a=\frac Fm=\frac{F}{2(m_p+m_n)}=\frac{2.24\cdot10^{-16}}{2\cdot(1.673+1.675)\cdot10^{-27}}=3.35\cdot10^{10}~\frac{m}{s^2}.$