Question #153225

A charge is released from rest in a

uniform electric field with a magnitude of 4.5 × 10^3 V/m. The charge moves 350 cm as a

result. What is the potential difference between the charge’s initial and final positions?


Expert's answer

Answer

the potential difference between the charge’s initial and final positions is given by

ΔV=E×d\Delta V=E\times d

=4.5×103×3.5=4.5 × 10^3\times 3.5

=15,750 V


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