Answer
This is similiar as Bohr model energy is given by
E=−13.6eVn2E=\frac{-13.6eV}{n^2}E=n2−13.6eV
the frequency of the radiation emitted by the atom
ν=Eh\nu=\frac{E}{h}ν=hE
Using above both equation
ν=Eh=13.6×1.6×10−196.6×10−34=3.3×1015Hz\nu=\frac{E}{h}=\frac{13.6\times1.6\times10^{-19}}{6.6\times10^{-34}}\\=3.3\times10^{15}Hzν=hE=6.6×10−3413.6×1.6×10−19=3.3×1015Hz
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