Answer
Magnetic field due to wire is given by
B=μ0I2πrB=\frac{\mu_0I}{2\pi r}B=2πrμ0I
B=4π×10−7×22π×3=1.33TeslaB=\frac{4\pi \times 10^{-7}\times 2}{2\pi \times3}=1.33 TeslaB=2π×34π×10−7×2=1.33Tesla
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